Redox Reactions - Examples
With the help of various redox reactions examples mentioned in this article, students will find it easier to understand the meaning of redox reactions and the chemical processes occurring in them.

What is a Redox Reaction?
The word redox is the acronym for reduction-oxidation that occur in a certain chemical reaction. Put more simply, these reactions are those sets of chemical equations in which the oxidation number of the atoms involved in the chemical reaction changes when the reaction occurs. This definition introduces us to another fundamental concept in chemistry that is of crucial importance, the oxidation number. Let us define it.
Oxidation number is a number that is exactly similar to the valency of an atom but oxidation number carries a sign with it. This sign expresses the nature of charge on the corresponding species when it is formed from a neutral atom. Let us understand this through an example. The oxidation number of chlorine in hydrochloric acid (HCl) is -1, in Chloric acid (HClO3) is +5 and in perchloric acid (HClO4) it is +7.
How do we calculate oxidation number? Well, for calculating oxidation number, one has to consider various oxidation states of all atoms in a molecule and then equate the sum of all of them to the net charge on the molecule. There are various rules for finding oxidation number of an atom in a molecule however, here we will just see how to find oxidation number of Cl in HClO3.
Oxidation number of H = +1
Oxidation number of Cl = Z (let us suppose)
Oxidation number of O = -2
Therefore, +1 + Z + 3 (-2) = 0 (since net charge on HClO3 = 0),
Hence, +1 + Z + (-6) = 0. This means, Z = +5.
So on a general note, oxidation generally involves any of the following changes:
- Loss of electrons
- Loss of hydrogen atoms
- Gain of oxygen
- Increase in oxidation state
- Gain of electrons
- Gain of hydrogen atoms
- Loss of oxygen atoms
- Decrease in oxidation state
Here is one of the simplest examples of these reactions, that will help you to get a better idea of this concept.
Formation of Hydrogen Fluoride
Reaction: H2 + F2 = 2HF
Substance oxidized: Hydrogen
Substance reduced: Fluorine
Oxidation Reaction: H2 → 2H+ + 2e-
Reduction Reaction: F2 + 2e- → 2F-
In the first reaction, hydrogen oxidizes by increasing its oxidation number from 0 to +1 while in the second reaction, fluorine is reduced by decreasing its oxidation number from 0 to -1. Eventually, net charge on the molecules formed is zero as number of electrons gained during oxidation are consumed during reduction process. Finally, the equation turns out to be,
H2 → 2H+ + 2e- + F2 + 2e- → 2F- = H2 + F2 = 2H+ + 2F-
H2 + F2 → 2H+ + 2F-→ 2HF
Some More Examples
Some more examples have been mentioned here. In these examples, only the complete reactions have been mentioned instead of the half cell reactions.
- Reaction between Fe(II) and CuSO4 solution: Fe + CuSO4 + → FeSO4 + Cu (Fe oxidized, Cu reduced)
- Oxidation of Fe(II) to Fe(III) by hydrogen peroxide and an acid: 2 Fe2+ + H2O2 + 2 H+ → 2 Fe3+ + 2 H2O
- Glucose oxidation to carbon dioxide: C6H12O6 + 6 O2 → 6 CO2 + 6 H2O
- Reaction between Potassium Permanganate and Sodium Sulfite: 2 KMnO4 + 3 Na2SO3 + H2O → 2 MnO2 + 3 Na2SO4 + 2 KOH
- Reaction of an acid and a base: 3 CuS + 8 HNO3 → 3 CuSO4 + 8 NO (g) + 4 H2O
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